Current transformation  ![]()
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Principle When very high current strengths are required on a technical
scale, e.g. for welding equipment or electric smelting furnaces,
then so-called heavy current transformers are used. Their secondary
coils have only a few turns of large diameter wire.
In the case of an ideal transformer under load, the primary and
secondary performances are equal, so that
Is ∕ Ip
= Np ∕ Ns
is valid. The students should recognise from this experiment that
the ratio Is
∕ Ip increases with increasing load, so
that Is
∕ Ip
≈ Np ∕ Ns
is true for the transformer under load. Benefits - No additional cable connections between the building blocks needed - clear arragned and quick setup
- Contact saftey due to puzzle blocks system
- Corrosion-free gold plated contacts
- Doubled earning sucess: Electric circuit diagram on top, real components can be seen unterside
Tasks How does a transformer perform under load? Set up a model of a transformer and use it to examine which
conformity to law is given when the transformer is under load. Scope of delivery |
Straight connector module, SB
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05601-01
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2
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Angled connector module, SB
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05601-02
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2
| |
Interrupted connector module with sockets, SB
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05601-04
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2
| |
Junction module, SB
|
05601-10
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2
| |
Angled connector module with socket, SB
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05601-12
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2
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On-off switch module, SB
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05602-01
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1
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Resistor module 50 Ohm, SB
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05612-50
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1
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Resistor module 100 Ohm, SB
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05613-10
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1
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Coil, 400 turns
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07829-01
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1
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Coil, 1600 turns
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07830-01
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1
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Iron core, U-shaped, laminated
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07832-00
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1
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Iron core, I-shaped, laminated
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07833-00
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1
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Tightening screw
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07834-00
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1
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Connecting cable, 32 A, red, various lengths
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07360-01
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2
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Connecting cable, 32 A, blue, various lengths
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07360-04
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2
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Connecting cable, 32 A, red, various lengths
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07361-01
|
2
| |
Connecting cable, 32 A, blue, various lengths
|
07361-04
|
2
| |
PHYWE Power supply, 230 V,DC: 0...12 V, 2 A / AC: 6 V, 12 V, 5 A
|
13506-93
|
1
| |
PHYWE Analog multimeter, 600V AC/DC, 10A AC/DC, 2 MΩ, overload protection
|
07021-11
|
2
|
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Service
